Gravitational potential energy
Lift something up and you fill its gravitational potential store.
gravitational potential energy = mass × gravitational field strength × height
Ep = m g h
Energy in J, mass in kg, g in N/kg, height in m. On Earth, g = 9.8 N/kg: the question will tell you which value to use. Recall it: none of the three boards puts it on the sheet.
- A 50 kg climber climbs 12 m. Take g = 9.8 N/kg.
- E = 50 × 9.8 × 12
- E = 5880 J
To find a height: h = E ÷ (m g). If the energy is in kJ, multiply by 1000 first.
Elastic potential energy
A stretched or squashed spring stores energy, as long as it is not stretched past its limit of proportionality.
elastic potential energy = 0.5 × spring constant × (extension)²
Ee = ½ k e²
k in newtons per metre (N/m), extension e in metres. This one is given on the equation sheet for AQA, Edexcel and OCR.
- A spring with k = 400 N/m is stretched 5 cm.
- e = 5 cm = 0.05 m
- E = ½ × 400 × 0.05² = 0.5 × 400 × 0.0025
- E = 0.5 J
Leave e in cm and you get 5000 J instead of 0.5 J. Convert before you square.
Energy is conserved
When nothing is wasted (no air resistance, no friction), energy lost from one store all turns up in another.
- A ball is dropped from 5 m. How fast is it going when it lands?
- Ep lost = Ek gained: m g h = ½ m v²
- The mass cancels: v² = 2 g h = 2 × 9.8 × 5 = 98
- v = √98 = 9.9 m/s (2 s.f.)
The same idea works for a swing (kinetic at the bottom becomes gravitational at the top: h = v² ÷ 2g) and for a spring launcher (½ k e² becomes ½ m v²). These two-step questions are usually on Higher papers.
Watch the stores swap in a pendulum
Set the length to 2 m and the start angle to 40°. Open Advanced, set gravity to 9.8 and turn on Energy bars, then start it. At each end the potential bar is full and the kinetic bar is empty; at the bottom they swap, and the total never changes. The bob drops 2 × (1 − cos 40°) = 0.47 m, so it should reach √(2 × 9.8 × 0.47) = 3.0 m/s at the bottom. Then add some damping: what happens to the total, and where has the energy gone?
Energy in a bouncing spring
Set the spring constant to 50 N/m, the mass to 2 kg and the amplitude to 0.4 m, and turn on Energy bars under Advanced. The energy readout is ½ × 50 × 0.4² = 4 J. Check the maximum speed readout (2 m/s): ½ × 2 × 2² is also 4 J. Kinetic at the middle, elastic at the ends, same total. Double the amplitude: by how much does the energy go up?
Your first potential energy calculation
Write E = m g h, use g = 9.8 N/kg as the question says, then the unit.