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Unit Circle with Exact Values

The unit circle is a circle of radius 1 centred on the origin, so the point at angle θ is (cos θ, sin θ). Drag the point to see the exact values.

°

1−11−1 cossin θ

0°

0 rad

On the positive x-axis

sin θ0
cos θ1
tan θ0

The point is at (cos θ, sin θ): (1, 0)

Sine and cosine graphs

Arrow keys move 1°, Page Up and Page Down move 15°.

How it works

Measure the angle θ anticlockwise from the positive x-axis. The radius joins the centre to the point. It is the hypotenuse of a right-angled triangle, and its length is 1.

The triangle's horizontal side is 1 × cos θ and its vertical side is 1 × sin θ. So the point on the circle is (cos θ, sin θ), and tan θ = sin θ ÷ cos θ.

Exact values from 0° to 90°

Learn these five rows. Every other special angle on the circle uses the same numbers with a different sign.

AngleRadianssin θcos θtan θ
0°0010
30°π/61/23/23/3
45°π/42/22/21
60°π/33/21/23
90°π/210undefined

You will also see tan 30° written as 1/3 and sin 45° as 1/2. They are the same numbers: 1/3 = 3/3 and 1/2 = 2/2.

Every special angle round the circle

Past 90°, find the reference angle (the acute angle between the radius and the x-axis), read its values from the table above, then give each one the sign for its quadrant.

AngleRadianssin θcos θtan θ
120°2π/33/2−1/2−3
135°3π/42/2−2/2−1
150°5π/61/2−3/2−3/3
180°π0−10
210°7π/6−1/2−3/23/3
225°5π/4−2/2−2/21
240°4π/3−3/2−1/23
270°3π/2−10undefined
300°5π/3−3/21/2−3
315°7π/4−2/22/2−1
330°11π/6−1/23/2−3/3
360°2π010

Key facts

  • Point on the circle: (cos θ, sin θ). x is cos θ and y is sin θ.
  • Tangent: tan θ = sin θ ÷ cos θ. It is undefined at 90° and 270°, because cos θ is 0 there and you cannot divide by 0.
  • Identity: sin²θ + cos²θ = 1 for every angle. It is Pythagoras on the triangle, whose hypotenuse is 1.
  • Signs (CAST): all three ratios are positive in the first quadrant, only sin in the second, only tan in the third and only cos in the fourth.
  • Symmetry: sin(180° − θ) = sin θ and cos(180° − θ) = −cos θ. Going the other way round, sin(−θ) = −sin θ and cos(−θ) = cos θ.
  • Period: the values repeat every 360°, so sin(θ + 360°) = sin θ and cos(θ + 360°) = cos θ.
  • Degrees to radians: multiply by π/180, so 30° = π/6 and 135° = 3π/4. To go back, multiply by 180/π.
Signs by quadrant: all three ratios are positive in the first quadrant, only sin in the second, only tan in the third and only cos in the fourth.Allpositivesinpositivetanpositivecospositive
Read CAST anticlockwise from the bottom right: Cos, All, Sin, Tan.

Worked examples

Example 1

Find the exact values of sin, cos and tan at 150°.

  1. 150° is in the second quadrant, where sin is positive and cos is negative.
  2. The reference angle is 180° − 150° = 30°.
  3. sin 30° = 1/2 and cos 30° = 3/2.
  4. So sin 150° = 1/2, cos 150° = −3/2 and tan 150° = (1/2) ÷ (−3/2) = −1/3 = −3/3.

Answer: sin 150° = 1/2, cos 150° = −3/2, tan 150° = −3/3.

Example 2

Solve sin θ = 1/2 for 0° ≤ θ < 360°.

  1. sin θ is positive, so θ is in the first or the second quadrant.
  2. sin 30° = 1/2, so the reference angle is 30°.
  3. First quadrant: θ = 30°. Second quadrant: θ = 180° − 30° = 150°.

Answer: θ = 30° or θ = 150° (π/6 or 5π/6 in radians).

Common mistakes

  • Giving cos a positive sign in the second quadrant: only sin is positive there.
  • Swapping sin and cos: x is cos θ and y is sin θ.
  • Writing a value for tan 90°: it is undefined, because cos 90° = 0.
  • Stopping at one answer: sin θ = 1/2 has two solutions between 0° and 360°, 30° and 150°.
  • Mixing up the units: check whether the question uses degrees or radians, and set your calculator to match. 150° is 5π/6 radians.

Learn this properly

Lessons from GCSE Maths on this topic: worked steps, then exam-style questions with new numbers every time.

See the whole courseThe full course, topic tests and mock papers come with Plus. See Plus

FAQ

Why is the point at (cos θ, sin θ)?
The radius is the hypotenuse of the right-angled triangle and it has length 1. The horizontal side is 1 × cos θ and the vertical side is 1 × sin θ, so those are the point's coordinates.
Where do exact values like √3/2 come from?
From two special triangles. Half of an equilateral triangle with sides 2 gives sides 1, 3 and 2, so sin 60° = 3/2 and cos 60° = 1/2. A right-angled isosceles triangle with legs 1 has hypotenuse 2, so sin 45° = cos 45° = 1/2 = 2/2.
What is a reference angle?
It is the acute angle between the radius and the x-axis. An angle and its reference angle have the same sin, cos and tan apart from the sign, which depends on the quadrant.
Why is tan 90° undefined?
tan θ = sin θ ÷ cos θ, and at 90° cos θ = 0, so tan 90° would mean dividing 1 by 0, which has no value. The graph of tan θ has a vertical asymptote at 90°, and the same happens at 270°.
Which exact values do I need for GCSE?
The content that AQA, Pearson Edexcel and OCR all follow (DfE G21) asks you to know sin and cos of 0°, 30°, 45°, 60° and 90°, and tan of 0°, 30°, 45° and 60°, without a calculator. That is the first table on this page, and it is on both Foundation and Higher papers.
Why does sin 30° = cos 60°?
In a right-angled triangle the other two angles add up to 90°, so the side opposite 30° is the side adjacent to 60°. That makes sin 30° and cos 60° the same ratio, 1/2. In general sin θ = cos(90° − θ), which is why sin 60° = cos 30° = 3/2 as well.